ExamPlay Light Logo
Đăng nhập

JEE MAIN - Mathematics Hindi (2015 (Offline) - No. 4)

माना $$\alpha$$ तथा $$\beta$$ द्विघात समीकरण $$x^{2}-6 x-2=0$$ के मूल हैं। यदि $$\mathrm{n} \geqslant 1$$ के लिए, $$\mathrm{a}_{\mathrm{n}}=\alpha^{\mathrm{n}}-\beta^{\mathrm{n}}$$ है, तो $$\frac{\mathrm{a}_{10}-2 \mathrm{a}_{8}}{2 \mathrm{a}_{9}}$$ का मान है :
$$3$$
$$ - 3$$
$$6$$
$$ - 6$$

Bình luận (0)

Đăng nhập để bình luận
Quảng cáo
BrainBehindX Inc Logo
©2026; Được cung cấp bởi BrainBehindX Inc